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674. Longest Continuous Increasing Subsequence

Array

Problem - Longest Continuous Increasing Subsequence

Easy

Given an unsorted array of integers nums, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.

A continuous increasing subsequence is defined by two indices l and r (l < r) such that it is [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]] and for each l <= i < r, nums[i] < nums[i + 1].

 

Example 1:

Input: nums = [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5] with length 3.
Even though [1,3,5,7] is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element
4.

Example 2:

Input: nums = [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2] with length 1. Note that it must be strictly
increasing.

 

Constraints:

  • 1 <= nums.length <= 104
  • -109 <= nums[i] <= 109

Solutions

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class Solution:
    def findLengthOfLCIS(self, nums: List[int]) -> int:
        result = count = 1
        for i, val in enumerate(nums[1:]):
            if nums[i] < val:
                count += 1
                result = max(result, count)
            else:
                count = 1
        return result

Submission Stats:

  • Runtime: 2 ms (75.13%)
  • Memory: 18.6 MB (85.70%)